Panjang = p = p cm
Lebar = l = 5 cm
Tinggi = t = 10 cm
Luas permukaan balok = 340 cm2
Luas permukaan balok
340 = (2×p×l)+(2×p×t)+(2×l×t)
340 = (2×p×5)+(2×p×10)+(2×5×10)
340 = 10p + 20p + 100
340 = 100 + 30p
340 - 100 = 30p
240 = 30p
p = 240÷30 = 8 cm
Volume balok = p×l×t = 8×5×10 = 400 cm2