Diketahui ∑k=1020k2=2.585\sum_{k=10}^{20}k^2=2.585∑k=1020k2=2.585. Nilai dari ∑k=1222(k2−4k+4)=....\sum_{k=12}^{22}\left(k^2-4k+4\right)=....∑k=1222(k2−4k+4)=....
2.5852.5852.585
2.5582.5582.558
5.2855.2855.285
8.5528.5528.552
5.5825.5825.582